can someone plz explain the implications? will it mean that tractor's volume fader will not move as someone turn the pot in the beginning and it will move faster towards max as someone is turning it up?
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can someone plz explain the implications? will it mean that tractor's volume fader will not move as someone turn the pot in the beginning and it will move faster towards max as someone is turning it up?
i think the pot will employ whatever technology is cost-effective, regardless of curve. then you transform the curve in software to whatever you want. (i do not know if this is actually true. but given that adjustments of the response curve are completely trivial to implement in software, i cannot imagine it being different from the way i stated.)
as for logarithmic vs linear:
a pot with a linear curve assigned to it has a linear effect (doh!) on the variable it controls. that means, regardless of the pot's current position, moving the pot by an increment x will change the variable it controls by a fixed amount.
this is not true of a logarithmic curve (which is convex). if the pot is near its minimum position, moving the pot by an increment x will change the variable it controls by an amount that is small (in absolute value). if the pot is near its maximum position, moving it by an increment x will change the variable it controls by an amount that is large (again, in absolute value).
as a concrete example, as you move up a linear volumefader, you will hear a gradual, smooth increase in volume. as you move up a logarithmic fader, first it appears the fader has almost no effect on volume. but, when the fader is already a good fraction of the way up, further movements have larger and larger effects on the volume. so the logarithmic fader is much flatter near its minimum position but much steeper near its maximum position. (i know i'm repeating myself here. it's just for clarity's sake, i know what convex means.)